![]() ![]() The AGE() function two value as a timestamp to find the ages between the two timestamps. The AGE() function returns the result as an interval something like this 1 year 2 months 3 days and etc. To find the ages between two timestamps, the AGE() function is used. How to Find PostgreSQL DateDiff using Age() So the months between two dates ‘‘ and ‘’ is 3. And this part ( DATE_PART(‘MONTH’, DATE ‘’) – DATE_PART(‘MONTH’, DATE ‘’)) month as -9 then this -9 is added to 12 which is 12-9 =3.This part (DATE_PART(‘YEAR’, DATE ‘’) – DATE_PART(‘YEAR’, DATE ‘’)) returns the year as 1 and multiplied by 12 which is 12 * 1 = 12.Let’s understand each part of the above query to know how months are calculated using the DATE_PART() function: Then the second ( DATE_PART(‘MONTH’, DATE ‘’) – DATE_PART(‘MONTH’, DATE ‘’)) function extracts the month between two dates and then adds the result of the first DATE_PART() function to the second result returned by second DATE_PART() function. In the above query to compute the months between two dates, the first (DATE_PART(‘YEAR’, DATE ‘’) – DATE_PART(‘YEAR’, DATE ‘’)) function extracts the year between two dates, and then returned year is multiplied by 12. ![]() (DATE_PART('MONTH', DATE '') - DATE_PART('MONTH', DATE '')) AS month_datediff The DATE_PART() function takes two values, the field name which is the unit of the date and time such as year, day, months and etc, and the second value is the source which is the date and time value from which a specific field is extracted.Ĭheck the below examples to find the datediff in months between the two dates. So here you will see how to use the DATE_PART() function to find the difference between two dates. To extract the sub-fields such as minute, year, second, day, hour and etc, from the given date and time, use the DATE_PART() function. How to Find PostgreSQL DateDiff using DATE_PART() If you look at the above statement, The EXTRACT() function extracted the YEAR from both dates, then using the minus (-) operator between the extracted YEAR, the year difference is computed which is 4 in this case as you can see in the output. SELECTĮXTRACT(YEAR FROM DATE '') - EXTRACT(YEAR FROM DATE '') AS DATEDIFF_YEAR Use the below statement to find the year’s differences between the two dates. Let’s see how to use the EXTRACT() to find the date differences. The EXTRACT() function accept two value, the source also called the date and time value, and the second is field name like year, month and etc, that you want to extract from that date and time value. In simple words, When you need to find the specific field of the given date and time value, you can use this function. The EXTRACT() function gets the minutes, seconds, dates, years, months and etc, from the given date and time or timestamp value. How to Find PostgreSQL DateDiff using Extract() Let’s check some of the examples and find the date differences. To get the same functionality as DATEDIFF, you can use the minus (-) operator with different functions such as EXTRACT(), DATE_PART() and etc, to find the difference between the two dates. But this kind of function doesn’t exist in PostgreSQL. There is a function called DATEDIFF in other database software such as Oracle, SQL and etc, to compute the difference between the two dates. How to Find PostgreSQL DateDiff using Age().How to Find PostgreSQL DateDiff using DATE_PART().How to Find PostgreSQL DateDiff using Extract().
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